$4 x-3 y=24$

$\therefore 4 x-24=3 y$

$\therefore y=\frac{4 x-24}{3}$

Taking $x=0,$ we get $y=\frac{4(0)-24}{3}=\frac{-24}{3}=-8$

So, $(0,-8)$ is a solution of the given equation.

Taking $x=3,$ we get

$y=\frac{4(3)-24}{3}=\frac{-12}{3}=-4$

So, $(3,-4)$ is a solution of the given

equation. Taking $x=6,$ we get $y=\frac{4(6)-24}{3}=\frac{0}{3}=0$

So, $(6,0)$ is a solution of the given equation. Taking $x=9,$ we get $y=\frac{4(9)-24}{3}=\frac{12}{3}=4$

So, $(9,4)$ is a solution of the given equation.

So, four of the infinitely many solutions

of the given equation are

$(0,-8),(3,-4),(6,0)$ and $(9,4)$