4. Linear Equations in Two Variables
medium

Write four solutions for each of the following equations

$3 x+5 y=0$

Option A
Option B
Option C
Option D

Solution

$3 x+5 y=0$

$\therefore 5 y=-3 x$

$\therefore y=\frac{-3 x}{5}$

Taking $x=0,$ we get $y=\frac{-3(0)}{5}=\frac{0}{5}=0$

So, $(0,0)$ is a solution of the given equation.

Taking $x=5,$ we get $y=\frac{-3(5)}{5}=\frac{-15}{5}=-3$

So, $(5,-3)$ is a solution of the given

equation. Taking $x=-5,$ we get $y=\frac{-3(-5)}{5}=\frac{15}{5}=3$

So, $(-5,3)$ is a solution of the given equation.

Taking $x=10,$ we get $y=\frac{-3(10)}{5}=\frac{-30}{5}=-6$

So, $(10,-6)$ is a solution of the given equation.

So, four of the infinitely many solutions of the given equation are

$(0,0),(5,-3),(-5,3)$ and $(10,-6)$

Standard 9
Mathematics

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