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4. Linear Equations in Two Variables
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Write four solutions for each of the following equations
$3 x+5 y=0$
Option A
Option B
Option C
Option D
Solution
$3 x+5 y=0$
$\therefore 5 y=-3 x$
$\therefore y=\frac{-3 x}{5}$
Taking $x=0,$ we get $y=\frac{-3(0)}{5}=\frac{0}{5}=0$
So, $(0,0)$ is a solution of the given equation.
Taking $x=5,$ we get $y=\frac{-3(5)}{5}=\frac{-15}{5}=-3$
So, $(5,-3)$ is a solution of the given
equation. Taking $x=-5,$ we get $y=\frac{-3(-5)}{5}=\frac{15}{5}=3$
So, $(-5,3)$ is a solution of the given equation.
Taking $x=10,$ we get $y=\frac{-3(10)}{5}=\frac{-30}{5}=-6$
So, $(10,-6)$ is a solution of the given equation.
So, four of the infinitely many solutions of the given equation are
$(0,0),(5,-3),(-5,3)$ and $(10,-6)$
Standard 9
Mathematics
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