નિત્યસમ $(vi) :$ 

$(x+y)^{3}=x^{3}+y^{3}+3 x y(x+y),$

$\left[\frac{3}{2} x+1\right]^{3}=\left(\frac{3}{2} x\right)^{3}+(1)^{3}+3\left(\frac{3}{2} x\right) (1) \left[\frac{3}{2} x+1\right]$

$=\frac{27}{8} x^{3}+1+\frac{9}{2} x\left[\frac{3}{2} x+1\right]$

$=\frac{27}{8} x^{3}+1+\frac{27}{4} x^{2}+\frac{9}{2} x$

$=\frac{27}{8} x^{3}+\frac{27}{4} x^{2}+\frac{9}{2} x+1$