Write following cubes in expanded form : (3 a+4 b)^{3}

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2. Polynomials

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Write the following cubes in the expanded form : $(3 a+4 b)^{3}$

Option A

Option B

Option C

Option D

Solution

Comparing the given expression with $(x+y)^{3},$ we find that

$x=3 a$ and $ y=4 b$

So, using Identity $VI$, we have :

$(3 a+4 b)^{3} =(3 a)^{3}+(4 b)^{3}+3(3 a)(4 b)(3 a+4 b) $

$=27 a^{3}+64 b^{3}+108 a^{2} b+144 a b^{2}$

Standard 9

Mathematics

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