‘At surface of a charged conductor electrostatic field must be normal to surface at every poin

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2. Electric Potential and Capacitance

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‘At the surface of a charged conductor electrostatic field must be normal to the surface at every point’. Explain.

Option A

Option B

Option C

Option D

Solution

If $\overrightarrow{\mathrm{E}}$ were not normal to the surface, it would have some non-zero component along the surface. Free charges on the surface of the conductor would then experience force and move. Hence, conductor does not remains in stable situation.

Therefore, $\vec{E}$ should have no tangential component parallel to the surface in stable situation. Thus, electrostatic field at the surface of a charged conductor must be normal to the surface at every point. (For a conductor without any surface charge density, field is zero even at the surface).

$\left[\because 0=\frac{\sigma}{\epsilon_{0}}\right]$

Standard 12

Physics

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easy

‘At the surface of a charged conductor electrostatic field must be normal to the surface at every point’. Explain.

Solution

Similar Questions

The dielectric strength of air at $NTP$ is $3 \times {10^6}\,V/m$ then the maximum charge that can be given to a spherical conductor of radius $3\, m$ is

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