Gujarati
2. Electric Potential and Capacitance
medium

The dielectric strength of air at $NTP$ is $3 \times {10^6}\,V/m$ then the maximum charge that can be given to a spherical conductor of radius $3\, m$ is

A

$3 \times {10^{ - 4}}\,C$

B

$3 \times {10^{ - 3}}\,C$

C

$3 \times {10^{ - 2}}\,C$

D

$3 \times {10^{ - 1}}\,C$

Solution

(b) By using $E = 9 \times {10^9} \times \frac{Q}{{{R^2}}}$
$==>$ $3 \times {10^6} = 9 \times {10^9} \times \frac{Q}{{{{(3)}^2}}}$ $==>$ $Q = 3 \times {10^{ – 3}}\,C$

Standard 12
Physics

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