Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

............  $gm$ of a liquid of specific heat $0.2$ at a temperature $40°C$ must be mixed with $100 \,gm$ of a liquid of specific heat of $0.5 $ at a temperature $20°C,$ so that the final temperature of the mixture becomes $32°C$

A

$175$

B

$300$

C

$295$

D

$375$

Solution

(d) Temperature of mixture $\theta = \frac{{{m_1}{c_1}{\theta _1} + {m_2}{c_2}{\theta _2}}}{{{m_1}{c_1} + {m_2}{\theta _2}}}$

$\Rightarrow$ $32 = \frac{{{m_1} \times 0.2 \times 40 + 100 \times 0.5 \times 20}}{{{m_1} \times 0.2 + 100 \times 0.5}}$ $\Rightarrow$ ${m_1} = 375\,gm$

Standard 11
Physics

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