A =2 hat{ i }+hat{ j }, B =3 hat{ j }-hat{ k } and C =6 hat{ i }-2 hat{ k } Value of A -2 B +3 C wou

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3-1.Vectors

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$A =2 \hat{ i }+\hat{ j }, B =3 \hat{ j }-\hat{ k }$ and $C =6 \hat{ i }-2 \hat{ k }$ Value of $A -2 B +3 C$ would be

A

$20 \hat{ i }+5 \hat{ j }+4 \hat{ k }$

B

$20 \hat{ i }-5 \hat{ j }-4 \hat{ k }$

C

$4 \hat{ i }+5 \hat{ i }+20 \hat{ k }$

D

$5 \hat{ i }+4 \hat{ j }+10 \hat{ k }$

Solution

(b)

$A -2 B +3 C =(2 \hat{ i }+\hat{ j })-2(3 \hat{ i }-\hat{ k })+3(6 \hat{ i }-2 \hat{ k })$

$=20 \hat{ i }-5 \hat{ j }-4 \hat{ k }$

Standard 11

Physics

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