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11.Thermodynamics
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$P-V$ diagram of an ideal gas is as shown in figure. Work done by the gas in process $ABCD$ is

A
$4P_0V_0$
B
$2P_0V_0$
C
$3P_0V_0$
D
$P_0V_0$
Solution
$W_{AB} = -P_0V_0, W_{BC} = 0$ and $W_{CD} = 4P_0V_0$
$\Rightarrow W_{ABCD} = -P_0V_0 + 0 + 4P_0V_0 = 3P_0V_0$
Standard 11
Physics
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