10,gm of ice at 0,^oC is mixed with 'm',gm of water at 50,^oC . ........ gm is minimum value

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10-1.Thermometry, Thermal Expansion and Calorimetry

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$10\,gm$ of ice at $0\,^oC$ is mixed with $'m'\,gm$ of water at $50\,^oC$ . ........ $gm$ is minimum value of $m$ so that ice melts completely. ( $L_f = 80\,cal/gm$ and $S_W = 1\,cal/gm-\,^oC$ )

A

$32$

B

$20$

C

$40$

D

$16$

Solution

Heat given = Heat taken
$10(80) = m(50)$
$m = 16$

Standard 11

Physics

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