When $0.93\,watt-hour$ of energy is supplied to a block of ice weighing $10\,g,$ it is found that

$1\ gm$ of ice at $0^o C$ is mixed with $1gm$ of water at $100^o C$ the resulting temperature will be ………. $^oC$ 

$250\,gm$ of water and an equal volume of alcohol of mass $200\,gm$ are placed successively in the same calorimeter and cools from $60^{\circ}\,C$ to $55^{\circ}\,C$ in $130\,sec$ and $67 sec$ respectively. If the water equivalent of the calorimeter is $10\,gm$. , then the specific heat of alcohol in cal/gm $cal / gm ^{\circ}\,C$ is

$10\; gm$ of ice cubes at $0\;^{\circ} C$ are released in a tumbler (water equivalent $55\; g$ ) at $40\;^{\circ} C$. Assuming that negligible heat is taken from the surroundings, the temperature(in $^o C$) of water in the tumbler becomes nearely $(L_f=80\; cal / g )$

$10\,gm$ of ice at $0\,^oC$ is mixed with $'m'\,gm$ of water at $50\,^oC$ . …….. $gm$ is minimum value of $m$ so that ice melts completely. ( $L_f = 80\,cal/gm$ and $S_W = 1\,cal/gm-\,^oC$ )