1,kg of a diatomic gas is at a pressure of 8×10^4, N/m^2 . density of gas is 4, kg/m^3 . energy of

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12.Kinetic Theory of Gases

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$1\,kg$ of a diatomic gas is at a pressure of $8\times10^4\, N/m^2$. The density of the gas is $4\, kg/m^3$. What is the energy of the gas due to its thermal motion

$3\times10^4\, J$

$5\times10^4\, J$

$6\times10^4\, J$

$7\times10^4\, J$

Solution

For $1\, kg$ gas energy, $E=\frac{1}{2} \mathrm{RT}$

As $P=\rho r$ T there fore $R T=P / \rho$

$\begin{array}{ll}{\mathrm{E}=\frac{5}{2} \times \frac{8 \times 10^{4}}{4}} & {[\mathrm{f}=5 \text { for diatomic gas }]} \\ {\mathrm{E}=5 \times 10^{4} \text { Joule }}\end{array}$

Standard 11

Physics

The value of critical temperature in terms of van der Waals' constants $a$ and $b$ is given by

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A gaseous mixture consists of $16\, g$ of helium and $16\, g$ of oxygen. The ratio $(C_p/ C_v)$ of the mixture is

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A closed vessel contains $8\,gm$ of oxygen and $7\,gm$ of nitrogen. The total pressure is $10\,atm$ at the given temperature. If all the oxygen is removed from the system without permitting any change in temperature, then the pressure will become (in atmosphere)

normal

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Two identical glass bulbs are interconnected by a thin glass tube at $0^o\ C$. A gas is filled in these bulb is placed in ice and another bulb is placed in hot bath, then the pressure of the gas becomes $1.5\ times$. The temperature of hot bath will be …… $^oC$

normal

$1\,kg$ of a diatomic gas is at a pressure of $8\times10^4\, N/m^2$. The density of the gas is $4\, kg/m^3$. What is the energy of the gas due to its thermal motion

Solution

Similar Questions

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