Kₓ for NH₄OH is 1.8× 10^{-5}. [mathop Olimits^Theta H] of 0.1,M,NH₄OH is

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6-2.Equilibrium-II (Ionic Equilibrium)

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$K_b$ for $NH_4OH$ is $1.8\times 10^{-5}.$ The $[\mathop O\limits^\Theta H]$ of $0.1\,M\,NH_4OH$ is

A

$5.0\times 10^{-2}$

B

$4.20\times 10^{-3}$

C

$1.34\times 10^{-3}$

D

$1.8\times 10^{-6}$

Solution

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Standard 11

Chemistry

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