K_{sp} for BaSO₄ at 25,^oC is 1.1 × 10^{-10} . To make new solubility equal to 1.1 × 10^{-8} , i

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6-2.Equilibrium-II (Ionic Equilibrium)

medium

$K_{sp}$ for $BaSO_4$ at $25\,^oC$ is $1.1 \times 10^{-10}$. To make the new solubility equal to $1.1 \times 10^{-8}$, it is necessary to use the solution of $Na_2SO_4$ of the following concentration....$M$

A

$0.1$

B

$0.01$

C

$1$

D

$0.001$

Solution

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Standard 11

Chemistry

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