V^2 versus s -graph of a particle moving in a straight line is as shown in figure. From graph some c

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2.Motion in Straight Line

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$v^2$ versus $s$-graph of a particle moving in a straight line is as shown in figure. From the graph some conclusions are drawn. State which statement is wrong?

AThe given graph shows a uniformly accelerated motion

BInitial velocity of particle is zero

CCorresponding $s-t$ graph will be a parabola

DNone of the above

Solution

(b)
For uniformly accelerate motion, $v^2=u^2+2 a s$, i.e. $v^2$ versus $s$ graph is a straight line with intercept $u^2$ and slope $2 a$. Since, intercept in non-zero, initial velocity is non-zero.

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Solution

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