- Home
- Standard 11
- Physics
2.Motion in Straight Line
medium
A body starts from rest with an acceleration $a_{1},$ after two seconds another body $B$ starts from rest with an acceleration $a _{2}$. If they travel equal distance in fifth second, after the starts of $A$, the ratio $a _{1}: a _{2}$ will be equal to
A$9: 5$
B$5: 7$
C$5: 9$
D$7: 9$
(AIIMS-2019)
Solution
The distance covered in fifth second for first body is equal to the distance travelled in $3^{\text {rd }}$ second for second body, $S _{5}= S _{3}$
$S_{t}= u +\frac{(2 t -1) a}{2}$
$S_{5}=0+\frac{(2 \times 5-1) a}{2}$
$S_{5}=\frac{9 a_{1}}{2}$
$S_{3}=0+\frac{5}{2} a_{2}=\frac{5}{2} a_{2}$
$\frac{9 a_{1}}{2}=\frac{5}{2} a_{2}$
$\frac{a_{1}}{a_{2}}=\frac{5}{9}$
$S_{t}= u +\frac{(2 t -1) a}{2}$
$S_{5}=0+\frac{(2 \times 5-1) a}{2}$
$S_{5}=\frac{9 a_{1}}{2}$
$S_{3}=0+\frac{5}{2} a_{2}=\frac{5}{2} a_{2}$
$\frac{9 a_{1}}{2}=\frac{5}{2} a_{2}$
$\frac{a_{1}}{a_{2}}=\frac{5}{9}$
Standard 11
Physics
Similar Questions
hard