50, gm of copper is heated to increase its temperature by 10,^oC . If same quantity of heat is given

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10-1.Thermometry, Thermal Expansion and Calorimetry

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$50\, gm$ of copper is heated to increase its temperature by $10\,^oC$. If the same quantity of heat is given to $10\, gm$ of water, the rise in its temperature is ........ $^oC$ (Specific heat of copper $=420\, Joule\, kg^{-1}\,^oC^{-1}$)

A

$5$

B

$6$

C

$7$

D

$8$

Solution

Heat absorbed by copper=heat absorbed by water

Heat absorbed $=$ mass $\times$ specific heat $\times$ temperature difference

$\Rightarrow 50 \times 0.42 \times 10=10 \times 4.2 \times \Delta T$

$\Rightarrow \Delta T=5^{\circ} C$

Standard 11

Physics

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