A rod is fixed between two points at 20,^oC . coefficient of linear expansion of material of rod is

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A rod is fixed between two points at $20\,^oC$ . The coefficient of linear expansion of material of rod is $1.1 \times 10^{-5}/\,^oC$ and Young's modulus is $1.2 \times 10^{11}\,N/m^2$. Find the stress developed in the rod if temperature of rod becomes $10\,^oC$

A

$1.32 \times 10^7\,N/m^2$

B

$1.10 \times 10^{15}\,N/m^2$

C

$1.32 \times 10^{8}\,N/m^2$

D

$1.10 \times 10^{6}\,N/m^2$

Solution

Thermal stress $=\frac {F}{A}=Y \alpha \Delta t$

Standard 11

Physics

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