$(i)\,Al\,\xrightarrow{{{N_2}}}\,A$ $(ii)\,Al\,\xrightarrow{c}\,B$
Here $A$ and $B$ on hydrolysis respectively gives
$(i)\,Al\,\xrightarrow{{{N_2}}}\,A$ $(ii)\,Al\,\xrightarrow{c}\,B$
Here $A$ and $B$ on hydrolysis respectively gives
- A
$NH_3, \,C_2H_2$
- B
$NO,\, CH_4$
- C
$NH_3,\,CH_4$
- D
$NO,\,C_2H_2$
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