1, kg of ice at -10,^oC is mixed with 4.4, kg of water at 30,^oC . final temperature of mixture is&n

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10-1.Thermometry, Thermal Expansion and Calorimetry

normal

$1\, kg$ of ice at $-10\,^oC$ is mixed with $4.4\, kg$ of water at $30\,^oC$. The final temperature of mixture is ........ $^oC$ (specific heat of ice is $2100\, J/kg/k$)

$2.3$

$4.4$

$5.3$

$8.7$

Solution

Let temperature of mixture be $\theta$ then heat lost $=$ Heat gained $\Rightarrow 4.4 \times 1 \times(30=\theta)=1 \times 0.5 \times(10)+1 \times 80$

$+1 \times 1 \times(\theta-0)$

$\Rightarrow \theta=8.7^{\circ} \mathrm{C}$

Standard 11

Physics

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normal

$1\, kg$ of ice at $-10\,^oC$ is mixed with $4.4\, kg$ of water at $30\,^oC$. The final temperature of mixture is ........ $^oC$ (specific heat of ice is $2100\, J/kg/k$)

Solution

Similar Questions

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