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10-1.Thermometry, Thermal Expansion and Calorimetry
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Maximum density of $H_2O$ is at temperature
A
$32\,^oF$
B
$4\,^oK$
C
$4\,^oF$
D
$39.2\,^oF$
Solution
Maximum density at $4^{\circ} \mathrm{C}$
$\frac{\mathrm{T}_{\mathrm{C}}-0}{100-0}=\frac{\mathrm{T}_{\mathrm{F}}-32}{212-32}$
$\frac{4}{100}=\frac{T_{F}-32}{180}$
$\boxed{{{\text{T}}_{\text{F}}} = {{39.2}^\circ }{\text{F}}}$
Standard 11
Physics
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