- Home
- Standard 11
- Chemistry
6-2.Equilibrium-II (Ionic Equilibrium)
medium
${K_{sp}}$ for $Cr{(OH)_3}$ is $2.7 \times {10^{ - 31}}$. What is its solubility in moles / litre.
A
$1 \times {10^{ - 8}}$
B
$8 \times {10^{ - 8}}$
C
$1.1 \times {10^{ - 8}}$
D
$0.18 \times {10^{ - 8}}$
Solution
(a) $Cr{(OH)_3}\; \to \;\mathop {C{r^{ + 3}}}\limits_x + \mathop {3O{H^ – }}\limits_{3x} $
${K_{sp}} = x.{(3x)^3} = 27{x^4}$
$x = \sqrt[4]{{\frac{{{K_{sp}}}}{{27}}}}$ ; $x = \sqrt[4]{{\frac{{2.7 \times {{10}^{ – 31}}}}{{27}}}}$
$x = 1 \times {10^{ – 8}}$ $mole/litre.$
Standard 11
Chemistry
