Solubility product of Hg₂I₂ is equal to

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6-2.Equilibrium-II (Ionic Equilibrium)

medium

The solubility product of $Hg_2I_2$ is equal to

A

$\left[ {Hg_2^{ + 2}} \right]\left[ {{I^ - }} \right]$

B

$\left[ {H{g^{ + 2}}} \right]\left[ {{I^ - }} \right]$

C

$\left[ {H{g_2}^{ + 2}} \right]{\left[ {{I^ - }} \right]^2}$

D

${\left[ {H{g^{ + 2}}} \right]^2}{\left[ {{I^ - }} \right]^2}$

Solution

For $Hg _2 I _2$,

$Hg _2 I _2 \rightleftharpoons Hg _2{ }^{2+}+2 I ^{-}$

Let the solubility product be $K _{\text {sp }}$.

$K _{ sp }=\left[ Hg _2{ }^{2+}\right]\left[ I ^{-}\right]^2$

Standard 11

Chemistry

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