Assertion : In a free fall, weight of a body becomes effectively zero. Reason : Acceleration due to

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7.Gravitation

easy

$Assertion$ : In a free fall, weight of a body becomes effectively zero.
$Reason$ : Acceleration due to gravity acting on a body having free fall is zero.

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

If the Assertion is correct but Reason is incorrect.

If both the Assertion and Reason are incorrect.

(AIIMS-2011)

Solution

In a free fall, effective weight of a body becomes zero. The reason behind it is the normal force acting on the object is equal to mg which is same as the weight of the object. So, the object feels weightless. Actual weight during Free fall is mg.

The acceleration due to gravity on the object falling down is $9.8 \mathrm{m} / \mathrm{s}^{2} .$ It is non zero.

Standard 11

Physics

Weight of $1 \,kg$ becomes $1/6$ on moon. If radius of moon is $1.768 \times {10^6}\,m$, then the mass of moon will be

medium

Give the value of acceleration due to gravity at height $12\, km$ from the surface of earth.

easy

The percentage decrease in the weight of a rocket, when taken to a height of $32 km$ above the surface of earth will, be$…..\%$

(Radius of earth $=6400\,km$ )

medium

(JEE MAIN-2022)

The value of g on the earth's surface is $980\,cm/{\sec ^2}$. Its value at a height of $64 \,km$ from the earth's surface is …….. $cm/{\sec ^2}$

(Radius of the earth $R = 6400$ kilometers)

medium

Mass of moon is $7.34 \times {10^{22}}\,kg$. If the acceleration due to gravity on the moon is $1.4\,m/{s^2}$, the radius of the moon is $(G = 6.667 \times {10^{ – 11}}\,N{m^2}/k{g^2})$

easy

$Assertion$ : In a free fall, weight of a body becomes effectively zero. $Reason$ : Acceleration due to gravity acting on a body having free fall is zero.

Solution

Similar Questions

Weight of $1 \,kg$ becomes $1/6$ on moon. If radius of moon is $1.768 \times {10^6}\,m$, then the mass of moon will be

Give the value of acceleration due to gravity at height $12\, km$ from the surface of earth.

The percentage decrease in the weight of a rocket, when taken to a height of $32 km$ above the surface of earth will, be$…..\%$ (Radius of earth $=6400\,km$ )

The value of g on the earth's surface is $980\,cm/{\sec ^2}$. Its value at a height of $64 \,km$ from the earth's surface is …….. $cm/{\sec ^2}$ (Radius of the earth $R = 6400$ kilometers)

Mass of moon is $7.34 \times {10^{22}}\,kg$. If the acceleration due to gravity on the moon is $1.4\,m/{s^2}$, the radius of the moon is $(G = 6.667 \times {10^{ – 11}}\,N{m^2}/k{g^2})$

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$Assertion$ : In a free fall, weight of a body becomes effectively zero.
$Reason$ : Acceleration due to gravity acting on a body having free fall is zero.

The percentage decrease in the weight of a rocket, when taken to a height of $32 km$ above the surface of earth will, be$…..\%$

(Radius of earth $=6400\,km$ )

The value of g on the earth's surface is $980\,cm/{\sec ^2}$. Its value at a height of $64 \,km$ from the earth's surface is …….. $cm/{\sec ^2}$

(Radius of the earth $R = 6400$ kilometers)