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7.Gravitation
medium
The percentage decrease in the weight of a rocket, when taken to a height of $32 km$ above the surface of earth will, be$.....\%$
(Radius of earth $=6400\,km$ )
A
$1$
B
$3$
C
$4$
D
$0.5$
(JEE MAIN-2022)
Solution
Acceleration due to gravity at a height $h << R$ is
$g ^{\prime}= g \left(1-\frac{2 h }{ R }\right)$
$\therefore \frac{\Delta g }{ g }=\frac{2 h }{ R }$
$\Rightarrow \frac{\Delta g }{ g } \times 100=\frac{2 h }{ R } \times 100$
$=2 \times \frac{32}{6400} \times 100=1 \%$
Standard 11
Physics
