- Home
- Standard 11
- Physics
11.Thermodynamics
normal
$1\;g$ of water, of volume $1\; \mathrm{cm}^{3}$ at $100^{\circ} \mathrm{C},$ is converted into steam at same temperature under normal atmospheric pressure $\left(=1 \times 10^{5} \;\mathrm{Pa}\right) .$ The volume of steam formed equals $1671 \;\mathrm{cm}^{3} .$ If the specific latent heat of vaporisation of water is $2256\; \mathrm{J} / \mathrm{g}$, the change in intemal energy is.....$J$
A
$2423$
B
$2089$
C
$167$
D
$2256$
Solution
$\mathrm{Q}=\Delta \mathrm{U}+\mathrm{W} \Rightarrow \mathrm{mL}=\Delta \mathrm{U}+\mathrm{P}\left(\mathrm{V}_{2}-\mathrm{V}_{1}\right)$
$1(2256)=\Delta U+1 \times 10^{5}\left(1670 \times 10^{-6}\right) $$\Rightarrow \Delta U=2089 \mathrm{J}$
Standard 11
Physics
