${{\rm{H}}{{\rm{e}}_2}}$ molecule is not possible.
He $(Z=2)$, So, Total electron in $\mathrm{He}_{2}=4$
Electron configuration in $\mathrm{MO} \mathrm{He}_{2}:\left(\sigma_{1 s}\right)^{2}\left(\sigma_{1 s}^{*}\right)^{2}$
All electron are paired in $\mathrm{He}_{2}$, so it is diamagnetic.
Bond order $=\frac{1}{2}\left(\mathrm{~N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}\right)=\frac{1}{2}(2-2)=0$
Bond order in $\mathrm{He}_{2}$ is zero. So it is unstable and does not exist.
$\mathrm{MO}$ energy diagram of $\mathrm{He}_{2}$ is as under.
Which one is paramagnetic from the following
Total number of electron present in $\left(\pi^*\right)$ molecular orbitals of $\mathrm{O}_2, \mathrm{O}_2^{+}$and $\mathrm{O}_2^{-}$is ............
Which one is paramagnetic and has the bond order $1/2$
${N_2}$ and ${O_2}$ are converted into monoanions $N_2^ - $ and $O_2^ - $ respectively, which of the following statements is wrong
The bond order is maximum in