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According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding $O_2^ + $
Paramagnetic and bond order <${O_2}$
Paramagnetic and bond order >${O_2}$
Dimagnetic and bond order <${O_2}$
Dimagnetic and bond order >${O_2}$
Solution
(b) $(1)$
Bond order $= \frac{10-6}{2} = 2.0$
(Two unpaired electrons in antibonding molecular orbital)
$(2)$
Bond order $= \frac{10-5}{2} = 2.5$
(One unpaired electron in antibonding molecular orbital so it is paramagnetic)
${O_2} : {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{({\sigma ^*}2p_z)^2}$
$(\pi 2p_x^2 \equiv \pi 2p_y^2)\;({\pi ^*}2p_x^1 \equiv {\pi ^*}2p_y^1)\dots{(1)} $
${O_2^+} : {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{({\sigma ^*}2p_z)^2}$
$(\pi 2p_x^2 \equiv \pi 2p_y^2)\;({\pi ^*}2p_x^1 \equiv {\pi ^*}2p_y^0)\dots{(2)} $
