Sec θ=frac{13}{5}, then cos θ=ldots ldots ldots ldots

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8. Introduction to Trigonometry

easy

$\sec \theta=\frac{13}{5},$ then $\cos \theta=\ldots \ldots \ldots \ldots$

A

$\frac{12}{5}$

B

$\frac{5}{12}$

C

$\frac{5}{13}$

D

$\frac{13}{12}$

Solution

$\sec \theta=\frac{13}{5}\,\,\,\therefore \cos \theta=\frac{5}{13}$

Standard 10

Mathematics

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