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8. Introduction to Trigonometry
easy
$\cos (40-\theta)-\sin (50+\theta)=\ldots \ldots \ldots \ldots$
A
$\sin 40$
B
$\sin 10$
C
$2$
D
$0$
Solution
$\cos (40-\theta)-\sin (50+\theta)=\cos (40-\theta)-\cos [90-(50+\theta)]$
$=\cos (40-\theta)-\cos (40-\theta)$
$=0$
Standard 10
Mathematics