Cos (40-θ)-sin (50+θ)=ldots ldots ldots ldots

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8. Introduction to Trigonometry

easy

$\cos (40-\theta)-\sin (50+\theta)=\ldots \ldots \ldots \ldots$

A

$\sin 40$

B

$\sin 10$

C

$2$

D

$0$

Solution

$\cos (40-\theta)-\sin (50+\theta)=\cos (40-\theta)-\cos [90-(50+\theta)]$

$=\cos (40-\theta)-\cos (40-\theta)$

$=0$

Standard 10

Mathematics

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