Sin ^{2}(3 x+30)+cos ^{2}(2 x+45)=1, તો x=ldots ldots ldots ldots

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8. Introduction to Trigonometry

easy

$\sin ^{2}(3 x+30)+\cos ^{2}(2 x+45)=1,$ તો $x=\ldots \ldots \ldots \ldots$

A

$0$

B

$15$

C

$30$

D

$60$

Solution

Comparing $\sin ^{2}(3 x+30)+\cos ^{2}(2 x+45)=1$ with $\sin ^{2} \theta+\cos ^{2} \theta=1$,

we get $3 x+30=2 x+45$

$\therefore x=15$

Standard 10

Mathematics

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