99 % of a radioactive element will decay betw | vedclass

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Question

The decay rate is given as,

$N=N_{0}\left(\frac{1}{2}\right)^{n}$

$\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{n}$

$\frac{1}{100}=\left(\frac{1

Vedclass · Accepted Answer

$6$ and $7$ half lives

Vedclass · Answer

The decay rate is given as,

$N=N_{0}\left(\frac{1}{2}\right)^{n}$

$\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{n}$

$\frac{1}{100}=\left(\frac{1}{2}\right)^{n}$

$2^{n}=100$

The number of half lives is calculated as,

$2^{n}=100$

$n$ lies between the $6$ and $7 .$ So, the radioactive element will decay between $6$ and $7$ half lives.

$99 \%$ of a radioactive element will decay between

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