512 identical drops of mercury are charged to a potential of 2, V each. drops are joined to form a s

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2. Electric Potential and Capacitance

hard

$512$ identical drops of mercury are charged to a potential of $2\, V$ each. The drops are joined to form a single drop. The potential of this drop is ......... $V.$

A

$128$

B

$256$

C

$64$

D

$144$

(JEE MAIN-2021)

Solution

$Q =512 q$

Volume $_{i}=$ Volume $_{f}$

$512 \times \frac{4}{3} \pi r^{3}=\frac{4}{3} \pi R^{3}$

$2^{9} r ^{3}= R ^{3}$

$R =8 r$

$2=\frac{ kq }{ r }$

$V =\frac{ kQ }{ R }=\frac{ k 512 q }{8 r }$

$V =128$

Standard 12

Physics

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