A + ib > c + id can be explained only when

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4-1.Complex numbers

normal

$a + ib > c + id$ can be explained only when

A

$b = 0,c = 0$

B

$b = 0,d = 0$

C

$a = 0,c = 0$

D

$a = 0,d = 0$

Solution

(b)$a + ib > c + id$, it is defined if and only if imaginary parts must be equal to zero.
Therefore $ib = id = 0$

==> $b = d = 0$ $(\because i \ne 0)$

Standard 11

Mathematics

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