Cot x - tan x =

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3.Trigonometrical Ratios, Functions and Identities

easy

$\cot x - \tan x = $

A

$\cot \,2x$

B

$2{\cot ^2}x$

C

$2\,\,\cot \,2x$

D

${\cot ^2}\,2x$

Solution

(c) $\cot x – \tan x = \frac{{\cos x}}{{\sin x}} – \frac{{\sin x}}{{\cos x}} = \frac{{{{\cos }^2}x – {{\sin }^2}x}}{{\sin x\,\cos x}}$

$ = \frac{{2\,\cos \,2x}}{{\sin \,2x}} = 2\,\,\cot \,\,2x.$

Standard 11

Mathematics

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