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3.Trigonometrical Ratios, Functions and Identities
easy
$\cot x - \tan x = $
A
$\cot \,2x$
B
$2{\cot ^2}x$
C
$2\,\,\cot \,2x$
D
${\cot ^2}\,2x$
Solution
(c) $\cot x – \tan x = \frac{{\cos x}}{{\sin x}} – \frac{{\sin x}}{{\cos x}} = \frac{{{{\cos }^2}x – {{\sin }^2}x}}{{\sin x\,\cos x}}$
$ = \frac{{2\,\cos \,2x}}{{\sin \,2x}} = 2\,\,\cot \,\,2x.$
Standard 11
Mathematics
