Y - x + 3 = 0 is equation of normal at left( {3 + frac{3}{{√ 2 }},frac{3}{{√ 2 }}} right) to whi

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10-1.Circle and System of Circles

medium

$y - x + 3 = 0$ is the equation of normal at $\left( {3 + \frac{3}{{\sqrt 2 }},\frac{3}{{\sqrt 2 }}} \right)$ to which of the following circles

A

${\left( {x - 3 - \frac{3}{{\sqrt 2 }}} \right)^2} + {\left( {y - \frac{{\sqrt 3 }}{2}} \right)^2} = 9$

B

${\left( {x - 3 - \frac{3}{{\sqrt 2 }}} \right)^2} + {y^2} = 6$

C

${(x - 3)^2} + {y^2} = 9$

D

${(x - 3)^2} + {(y - 3)^2} = 9$

Solution

(c) Trick : Only option $(c)$ satisfies the given co-ordinates of the point.

Standard 11

Mathematics

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