Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

$10\, gm$ of ice at $0°C$ is mixed with $100 \,gm $ of water at $50°C.$ What is the resultant temperature of mixture........ $^oC$

A

$31.2$

B

$32.8$

C

$36.7$

D

$38.2$

Solution

(d) ${\theta _{{\rm{mix}}}} = \frac{{{m_W}{\theta _W} – \frac{{{m_{\,i}}{L_{\,i}}}}{{{c_W}}}}}{{{m_{\,i}} + {m_W}}}$ $ = \frac{{100 \times 50 – 10 \times \frac{{80}}{1}}}{{10 + 100}} \approx 38.2^\circ C$

Standard 11
Physics

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