Gujarati
14.Probability
medium

$n$ cadets have to stand in a row. If all possible permutations are equally likely, then the probability that two particular cadets stand side by side, is

A

$\frac{2}{n}$

B

$\frac{1}{n}$

C

$\frac{2}{{(n - 1)\,!}}$

D

None of these

Solution

(a) Total number of ways $ = n\,\,!$. Favourable cases $ = 2(n – 1)\,\,!$

Hence required probability $ = \frac{{2(n – 1)\,\,!}}{{n\,\,!}} = \frac{2}{n}$.

Standard 11
Mathematics

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