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14.Probability
medium
$n$ cadets have to stand in a row. If all possible permutations are equally likely, then the probability that two particular cadets stand side by side, is
A
$\frac{2}{n}$
B
$\frac{1}{n}$
C
$\frac{2}{{(n - 1)\,!}}$
D
None of these
Solution
(a) Total number of ways $ = n\,\,!$. Favourable cases $ = 2(n – 1)\,\,!$
Hence required probability $ = \frac{{2(n – 1)\,\,!}}{{n\,\,!}} = \frac{2}{n}$.
Standard 11
Mathematics