$n$ cadets have to stand in a row. If all possible permutations are equally likely, then the probability that two particular cadets stand side by side, is

  • A

    $\frac{2}{n}$

  • B

    $\frac{1}{n}$

  • C

    $\frac{2}{{(n - 1)\,!}}$

  • D

    None of these

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