Gujarati
14.Probability
medium

$5$ persons $A, B, C, D$ and $E$ are in queue of a shop. The probability that $A$ and $E$ always together, is

A

$\frac{1}{4}$

B

$\frac{2}{3}$

C

$\frac{2}{5}$

D

$\frac{3}{5}$

Solution

(c) Total number of ways $ = 5\,!$

Favourable number of ways $2\,.\,4\,!$

Hence required probability $ = \frac{{2\,.\,4\,!}}{{5\,!}} = \frac{2}{5}$.

Standard 11
Mathematics

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