If a leap year is selected at random, change that it will contain 53 Tuesdays ?

English

Gujarati

Hindi

14.Probability

medium

If a leap year is selected at random, what is the change that it will contain $53$ Tuesdays ?

A

$\frac{2}{7}$

B

$\frac{2}{7}$

C

$\frac{2}{7}$

D

$\frac{2}{7}$

Solution

In a leap year, there are $366$ days i.e., $52$ weeks and $2$ days.

In $52$ weeks, there are $52$ Tuesdays.

Therefore, the probability that the leap year will contain $53$ Tuesday is equal to the probability that the remaining $2$ days will be Tuesdays.

The remaining $2$ days can be

Monday and Tuesday

Tuesday and Wednesday

Wednesday and Thursday

Thursday and Friday

Friday and Saturday

Saturday and Sunday

Sunday and Monday

Total number of cases $=7$

Favorable cases $=2$

Probability that a leap year will have $53$ Tuesdays $=\frac{2}{7}$

Standard 11

Mathematics

Share

Similar Questions

There are two balls in an urn. Each ball can be either white or black. If a white ball is put into the urn and there after a ball is drawn at random from the urn, then the probability that it is white is

hard

(AIEEE-2012)

In a box there are $2$ red, $3$ black and $4$ white balls. Out of these three balls are drawn together. The probability of these being of same colour is

medium

The number lock of a suitcase has $4$ wheels, each labelled with ten digits i.e., from $0$ to $9 .$ The lock opens with a sequence of four digits with no repeats. What is the probability of a person getting the right sequence to open the suitcase?

hard

If the paper of $4$ students can be checked by any one of $7$ teachers, then the probability that all the $4$ papers are checked by exactly $2$ teachers is

normal

A bag contains $3$ white and $5$ black balls. If one ball is drawn, then the probability that it is black, is

normal