(p; wedge sim q) wedge (sim p vee q) is | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) Clearly, $(p\; \wedge \sim q) \wedge (p\; \vee \sim q)$ is a contradiction.


	
		
			
			$p$
			
			
			$q$
			
			
			$~p$

Vedclass · Accepted Answer

A contradiction

Vedclass · Answer

(a) Clearly, $(p\; \wedge \sim q) \wedge (p\; \vee \sim q)$ is a contradiction.


	
		
			
			$p$
			
			
			$q$
			
			
			$~p$
			
			
			$~q$
			
			
			$p \wedge ~q$
			
			
			$~p \vee q$
			
			
			$(p \wedge ~q) \wedge (~p \vee q)$
			
		
		
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
		
		
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
		
		
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
		
		
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$F$

$(p\; \wedge \sim q) \wedge (\sim p \vee q)$ is

Similar Questions

The statement $(\mathrm{p} \wedge(\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{q} \rightarrow \mathrm{r})) \rightarrow \mathrm{r}$ is :

Consider the following two propositions:

$P_1: \sim( p \rightarrow \sim q )$

$P_2:( p \wedge \sim q ) \wedge((\sim p ) \vee q )$

If the proposition $p \rightarrow((\sim p ) \vee q )$ is evaluated as $FALSE$, then

Which of the following Boolean expressions is not a tautology ?

Which of the following is a statement

If the inverse of the conditional statement $p \to \left( { \sim q\ \wedge \sim r} \right)$ is false, then the respective truth values of the statements $p, q$ and $r$ is