- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
easy
$64$ drops of mercury each charged to a potential of $10\,V$. They are combined to form one bigger drop. The potential of this drop will be.......$V$ (Assume all the drops to be spherical)
A
$160$
B
$80$
C
$10$
D
$640$
Solution
(a) $V = {n^{2/3}}v = {(64)^{2/3}} \times 10 = 160\,volt$
Standard 12
Physics