As shown in the figure, charges $ + q$ and $ - q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex $A$ is
As shown in the figure, charges $ + q$ and $ - q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex $A$ is
- [AIIMS 2002]
- A
$\frac{1}{{4\pi {\varepsilon _0}}}.\frac{{2q}}{{\sqrt {{a^2} + {b^2}} }}$
- B
Zero
- C
$\frac{1}{{4\pi {\varepsilon _0}}}.\frac{q}{{\sqrt {{a^2} + {b^2}} }}$
- D
$\frac{1}{{4\pi {\varepsilon _0}}}.\frac{{( - q)}}{{\sqrt {{a^2} + {b^2}} }}$
Similar Questions
At the centre of a half ring of radius $R=10 \mathrm{~cm}$ and linear charge density $4 \mathrm{n} \mathrm{C} \mathrm{m}^{-1}$, the potential is $x \pi V$. The value of $x$ is . . . . .
At the centre of a half ring of radius $R=10 \mathrm{~cm}$ and linear charge density $4 \mathrm{n} \mathrm{C} \mathrm{m}^{-1}$, the potential is $x \pi V$. The value of $x$ is . . . . .
- [JEE MAIN 2024]
Two identical positive charges are placed at $x =\, -a$ and $x = a$ . The correct variation of potential $V$ along the $x-$ axis is given by
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Assertion : For a non-uniformly charged thin circular ring with net charge is zero, the electric field at any point on axis of the ring is zero.
Reason : For a non-uniformly charged thin circular ring with net charge zero, the electric potential at each point on axis of the ring is zero.
Assertion : For a non-uniformly charged thin circular ring with net charge is zero, the electric field at any point on axis of the ring is zero.
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- [AIIMS 2015]
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- [JEE MAIN 2019]
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