જો બંધ પૃષ્ઠમાં દાખલ થતું અને બહાર આવતું ફલક્ | vedclass

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Question

Hint: Here, we have to apply gauss's law to find electric charge.

Solution:

We know that, electric flux $\phi_1$ (or electric field lines) e

Vedclass · Accepted Answer

$({\phi _2}\, - \,\,{\phi _1}){\varepsilon _0}$

Vedclass · Answer

Hint: Here, we have to apply gauss's law to find electric charge.

Solution:

We know that, electric flux $\phi_1$ (or electric field lines) entering in a closed

surface is -ve and electric flux $\phi_2$ (or electric field lines) leaving a closed surface is $+ve.$

Hence, net electric flux through the closed surface,

$\phi=\phi_2-\phi_1$

Now, according to Gauss' theorem, the net electric flux $\phi$ passing through a closed surface is equal to the $1 / \varepsilon_0$ times of the total charge $q$, inside the surface.

Step1: Apply gauss's law

Given, Net electric flux, $\phi=\left(\phi_2-\phi_1ight)$

$\phi=\frac{ q _{	ext {in }}}{\varepsilon_0}$

$\Rightarrow q_{	ext {in }}=\varepsilon_0 \phi$

$	herefore q_{	ext {in }}=\left(\phi_2-\phi_1ight) \varepsilon_0$

જો બંધ પૃષ્ઠમાં દાખલ થતું અને બહાર આવતું ફલક્સ અનુક્રમે $\phi_1$ અને $\phi_2$ છે. પૃષ્ઠની અંદરની બાજુએ વિદ્યુતભાર ........ હશે.

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