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4-1.Complex numbers
normal

જો ${(\sqrt 8  + i)^{50}}\,\, = \,\,{3^{49}}\,(a\,\, + \,ib)\,\,$ તો ${{\rm{a}}^{\rm{2}}}{\rm{  +  }}{{\rm{b}}^{\rm{2}}}{\rm{  =  ........ }}{\rm{. }}$

A

$3$

B

$4$

C

$8$

D

$9$

Solution

${(\sqrt 8  + i)^{50}}\,\, = \,\,{3^{49}}\,(a\,\, + \,ib)\,$ બંને બાજુ માનાક લઈ તેમના વર્ગ કરતાં,

$(8 + 1)^{50} = 3^{98}(a^2 + b^2)$

$3^{100} = 3^{98} (a^2 + b^2)$ 

$a^2 + b^2 = 9$

 

Standard 11
Mathematics

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