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4-1.Newton's Laws of Motion
medium
$60\;km/hr$ ની ઝડપથી જતી બાઇક $0.1\;km$ ત્રિજયામાં વળાંક લે છે,બાઇક સ્લીપ ન થાય તે માટે શિરોલંબ સાથે કેટલાના ખૂણે રાખવી જોઇએ?
A$\frac{{{{(60)}^2}}}{{0.1}}$
B${\tan ^{ - 1}}\left[ {\frac{{{{(50/3)}^2}}}{{100 \times 9.8}}} \right]$
C${\tan ^{ - 1}}\left[ {\frac{{100 \times 9.8}}{{{{(50/3)}^2}}}} \right]$
D${\tan ^{ - 1}}\sqrt {60 \times 0.1 \times 9.8} $
Solution
$v = 60\,km/hr\, = \frac{{50}}{3}\,m/s, \,r = 0.1km = 100\,m, \,g = 9.8\,m/{s^2}$
$\tan \theta = \frac{{{v^2}}}{{r\,g}}$
$\theta = {\tan ^{ – 1}}\left( {\frac{{{v^2}}}{{r\,g}}} \right) \,= {\tan ^{ – 1}}\left[ {\frac{{{{\left( {50/3} \right)}^2}}}{{100 \times 9.8}}} \right]$
$\tan \theta = \frac{{{v^2}}}{{r\,g}}$
$\theta = {\tan ^{ – 1}}\left( {\frac{{{v^2}}}{{r\,g}}} \right) \,= {\tan ^{ – 1}}\left[ {\frac{{{{\left( {50/3} \right)}^2}}}{{100 \times 9.8}}} \right]$
Standard 11
Physics
