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4-1.Newton's Laws of Motion
medium

 $ m_1 = 4m_2$  છે. $m_1 $ નો પ્રવેગ $a$ છે. $ m_2$ નો વેગ $0.4\, second$ સમયે  ........... $cm/s$ થાય.

A

$100$

B

$200$

C

$300$

D

$400$

Solution

$v = u + at$       [ $a = g/2 = \frac{{10}}{2} = 5\,m/{s^2}$]

$v = 0 + 5 \times 0.4$ $ = 2m/s\,\, = \,200\,cm/sec.$

Standard 11
Physics

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