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4-1.Newton's Laws of Motion
medium
$ m_1 = 4m_2$ છે. $m_1 $ નો પ્રવેગ $a$ છે. $ m_2$ નો વેગ $0.4\, second$ સમયે ........... $cm/s$ થાય.

A
$100$
B
$200$
C
$300$
D
$400$
Solution
$v = u + at$ [ $a = g/2 = \frac{{10}}{2} = 5\,m/{s^2}$]
$v = 0 + 5 \times 0.4$ $ = 2m/s\,\, = \,200\,cm/sec.$
Standard 11
Physics