…….. $N$  the maximum force for which both the block will move with same acceleration.

$A$ block of mass $M$ is placed on $a$ horizontal surface and it is tied with an inextensible string to $a$ block of mass, as shown in figure. A block of mass $m_0$ is also placed on $M$ If friction force exists between the block $M$ and the block $m_0$ and not between the block $M$ and the horizontal surface, then the minimum value of $\mu$ for which the block m remains stationary is

In figure, two blocks $M$ and $m$ are tied together with an inextensible and light string. The mass $M$ is placed on a rough horizontal surface with coefficient of friction $\mu$ and the mass $m$ is hanging vertically against a smooth vertical wall. The pulley is frictionless. Imagine a situation in which the given arrangement is placed inside an elevator that can move only in the vertical direction and compare the situation with the case when it is placed on the ground. When the elevator accelerates downward with $a_0( < g)$, then

The blocks are given velocity in the direction shown in figure. Co-efficient of friction between two blocks shown in figure is $μ = 0.5$. Take $g = 10\  m/s^2$

(considering $4\ kg$ block doesn't fall on ground)

Consider the following statements

$(i)$  Time when relative motion between them is stopped is $1.4\  second$.

$(ii)$  Time when relative motion between them is stopped in $1.2\  second$

$(iii)$  The common velocity of the two blocks is $8\  m/s$, towards right.

$(iv)$  The displacement of the $4\, kg$ block when relative motion stopped is$10.8\  m$.

Which of the fstatements is/are correct